Questions: What will be formed when CH2CH2 reacts with bromine in the dark?

What will be formed when CH2CH2 reacts with bromine in the dark?
Transcript text: What will be formed when $\mathrm{CH}_{2} \mathrm{CH}_{2}$ reacts with bromine in the dark?
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Solution

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Determine the product formed when \(\mathrm{CH}_{2} \mathrm{CH}_{2}\) reacts with bromine in the dark.

Reaction type

The reaction between \(\mathrm{CH}_{2} \mathrm{CH}_{2}\) (ethylene) and bromine (\(\mathrm{Br}_2\)) in the dark is an example of an addition reaction. In this reaction, the double bond in ethylene opens up, allowing each carbon to form a bond with a bromine atom.

Reaction mechanism

In the addition reaction, the \(\mathrm{Br}_2\) molecule approaches the \(\mathrm{CH}_{2} \mathrm{CH}_{2}\) double bond. The \(\pi\)-bond electrons of the double bond attack the bromine molecule, leading to the formation of a cyclic bromonium ion intermediate. This intermediate is then attacked by a bromide ion, resulting in the formation of 1,2-dibromoethane (\(\mathrm{CH}_{2} \mathrm{BrCH}_{2} \mathrm{Br}\)).

Product identification

The product of the reaction is 1,2-dibromoethane, which corresponds to option A: \(\mathrm{CH}_{2} \mathrm{BrCH}_{2} \mathrm{Br}\).

\(\boxed{\mathrm{CH}_{2} \mathrm{BrCH}_{2} \mathrm{Br}}\)

The answer is A: \(\mathrm{CH}_{2} \mathrm{BrCH}_{2} \mathrm{Br}\).

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