Questions: Simplify the expressions below as much as possible. Leave no negative numbers under radicals and no radicals in the denominator sqrt(-14) * sqrt(-2) = sqrt(-4) / sqrt(2) =

Simplify the expressions below as much as possible.
Leave no negative numbers under radicals and no radicals in the denominator

sqrt(-14) * sqrt(-2) =

sqrt(-4) / sqrt(2) =
Transcript text: Simplify the expressions below as much as possible. Leave no negative numbers under radicals and no radicals in denominat \[ \begin{array}{c} \sqrt{-14} \cdot \sqrt{-2}= \\ \frac{\sqrt{-4}}{\sqrt{2}}= \end{array} \]
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Solution

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Solution Steps

Solution Approach
  1. For the expression 142\sqrt{-14} \cdot \sqrt{-2}, recognize that the square root of a negative number involves imaginary numbers. Use the property ab=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} and simplify using ii where i=1i = \sqrt{-1}.

  2. For the expression 42\frac{\sqrt{-4}}{\sqrt{2}}, simplify the square roots separately, convert the negative square root to involve ii, and then simplify the fraction.

Step 1: Simplify 142\sqrt{-14} \cdot \sqrt{-2}

To simplify 142\sqrt{-14} \cdot \sqrt{-2}, we first recognize that the square root of a negative number involves the imaginary unit ii, where i=1i = \sqrt{-1}. Thus, we can express the square roots as:

14=14iand2=2i \sqrt{-14} = \sqrt{14} \cdot i \quad \text{and} \quad \sqrt{-2} = \sqrt{2} \cdot i

Using the property ab=ab\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}, we have:

142=(14i)(2i)=28i2 \sqrt{-14} \cdot \sqrt{-2} = (\sqrt{14} \cdot i) \cdot (\sqrt{2} \cdot i) = \sqrt{28} \cdot i^2

Since i2=1i^2 = -1, this simplifies to:

28(1)=28 \sqrt{28} \cdot (-1) = -\sqrt{28}

Simplifying 28\sqrt{28}, we get:

28=47=27 \sqrt{28} = \sqrt{4 \cdot 7} = 2\sqrt{7}

Thus, the expression simplifies to:

275.2915 -2\sqrt{7} \approx -5.2915

Step 2: Simplify 42\frac{\sqrt{-4}}{\sqrt{2}}

For the expression 42\frac{\sqrt{-4}}{\sqrt{2}}, we first simplify the square roots:

4=4i=2i \sqrt{-4} = \sqrt{4} \cdot i = 2i

2=2 \sqrt{2} = \sqrt{2}

Thus, the expression becomes:

2i2=22i \frac{2i}{\sqrt{2}} = \frac{2}{\sqrt{2}} \cdot i

Simplifying 22\frac{2}{\sqrt{2}}, we have:

22=2 \frac{2}{\sqrt{2}} = \sqrt{2}

Therefore, the expression simplifies to:

2i1.4142i \sqrt{2} \cdot i \approx 1.4142i

Final Answer

272i \begin{array}{c} -2\sqrt{7} \\ \sqrt{2} \cdot i \end{array}

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