Questions: The drawing below shows a mixture of molecules: Suppose the following chemical reaction can take place in this mixture: 4 HCl(g) + O2(g) → 2 H2O(g) + 2 Cl2(g) Of which reactant are there the most initial moles? Enter its chemical formula: Of which reactant are there the least initial moles? Enter its chemical formula: Which reactant is the limiting reactant? Enter its chemical formula:

The drawing below shows a mixture of molecules:

Suppose the following chemical reaction can take place in this mixture:
4 HCl(g) + O2(g) → 2 H2O(g) + 2 Cl2(g)

Of which reactant are there the most initial moles? Enter its chemical formula:

Of which reactant are there the least initial moles? Enter its chemical formula:

Which reactant is the limiting reactant? Enter its chemical formula:

Transcript text: The drawing below shows a mixture of molecules: Suppose the following chemical reaction can take place in this mixture: \[ 4 \mathrm{HCl}(g)+\mathrm{O}_{2}(g) \rightarrow 2 \mathrm{H}_{2} \mathrm{O}(g)+2 \mathrm{Cl}_{2}(g) \] \begin{tabular}{|l|l|} \hline Of which reactant are there the most initial moles? Enter its chemical formula: \\ \hline Of which reactant are there the least initial moles? Enter its chemical formula: \\ \hline Which reactant is the limiting reactant? Enter its chemical formula: \\ \hline \end{tabular}

Solution

Solution Steps

Step 1: Identify the molecules in the mixture

The drawing shows a mixture of molecules with the following key:
- Carbon (black)
- Hydrogen (white)
- Nitrogen (blue)
- Oxygen (red)
- Sulfur (yellow)
- Chlorine (green)

Step 2: Count the molecules of each reactant

According to the drawing:
- HCl (Hydrogen and Chlorine): There are 6 green (Chlorine) atoms, each paired with a white (Hydrogen) atom, making 6 HCl molecules.
- O₂ (Oxygen): There are 3 pairs of red (Oxygen) atoms, making 3 O₂ molecules.

Step 3: Determine the reactant with the most initial moles