Questions: At label 1 on the curve the predominant form of His is His^2- is - At label 2 on the curve the average net charge of His is -0.5 - At label 3 on the curve His is at its greatest buffering capacity - At label 4 on the curve pH=pKa of the carboxyl group - At label 5 on the curve histidine's carboxyl group is completely titrated with OH^- - At label 6 on the curve the predominant form of His is His^1- is -

At label 1 on the curve the predominant form of His is His^2- is - At label 2 on the curve the average net charge of His is -0.5 - At label 3 on the curve His is at its greatest buffering capacity - At label 4 on the curve pH=pKa of the carboxyl group - At label 5 on the curve histidine's carboxyl group is completely titrated with OH^- - At label 6 on the curve the predominant form of His is His^1- is -
Transcript text: At label 1 on the curve the predominant form of His is $\mathrm{His}^{2-}$ is - $\qquad$ At label 2 on the curve the average net charge of His is -0.5 - $\qquad$ At label 3 on the curve His is at its greatest buffering capacity - $\qquad$ At label 4 on the curve $\mathrm{pH}=\mathrm{pKa}$ of the carboxyl group - $\qquad$ At label 5 on the curve histidine's carboxyl group is completely titrated with $\mathrm{OH}^{-}$- $\qquad$ At label 6 on the curve the predominant form of His is $\mathrm{His}^{1-}$ is - $\qquad$
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Solution

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Solution Steps

Step 1: Analyze the titration curve
  • The titration curve for histidine shows pH changes as OH- equivalents are added.
  • Key points on the curve are labeled 1 through 6.
Step 2: Determine the predominant form at label 1
  • At label 1, the pH is around 9.
  • Histidine has three pKa values: approximately 1.8 (carboxyl group), 6.0 (imidazole group), and 9.2 (amino group).
  • At pH 9, the predominant form of histidine is His^0 (neutral), not His^2+.
Step 3: Determine the net charge at label 2
  • At label 2, the pH is around 10.
  • At this pH, the carboxyl group is deprotonated (-1), the imidazole group is neutral (0), and the amino group is deprotonated (0).
  • The net charge is -1.

Final Answer

  1. F
  2. F
  3. T
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