Questions: Define the domain of (s(x)=fracx+29(x-6)(x+7)).
Use interval notation for your answer.
The domain of (s(x)) is:
Transcript text: Define the domain of $s(x)=\frac{x+29}{(x-6)(x+7)}$.
Use interval notation for your answer.
The domain of $s(x)$ is: $\square$
Solution
Solution Steps
To find the domain of the function \( s(x) = \frac{x+29}{(x-6)(x+7)} \), we need to determine the values of \( x \) for which the function is defined. The function is undefined where the denominator is zero. Therefore, we need to find the values of \( x \) that make \( (x-6)(x+7) = 0 \) and exclude them from the domain.
Step 1: Identify the Function
We are given the function \( s(x) = \frac{x + 29}{(x - 6)(x + 7)} \). To determine the domain, we need to find the values of \( x \) that make the denominator zero.
Step 2: Find the Zeros of the Denominator
The denominator is given by \( (x - 6)(x + 7) \). Setting this equal to zero, we solve:
\[
(x - 6)(x + 7) = 0
\]
This gives us the solutions:
\[
x - 6 = 0 \quad \Rightarrow \quad x = 6
\]
\[
x + 7 = 0 \quad \Rightarrow \quad x = -7
\]
Step 3: Determine the Domain
The function \( s(x) \) is undefined at \( x = 6 \) and \( x = -7 \). Therefore, we exclude these points from the domain. The domain in interval notation is:
\[
(-\infty, -7) \cup (-7, 6) \cup (6, \infty)
\]
Final Answer
The domain of \( s(x) \) is \(\boxed{(-\infty, -7) \cup (-7, 6) \cup (6, \infty)}\).