Questions: Define the domain of (s(x)=fracx+29(x-6)(x+7)). Use interval notation for your answer. The domain of (s(x)) is:

Define the domain of (s(x)=fracx+29(x-6)(x+7)).

Use interval notation for your answer.

The domain of (s(x)) is:
Transcript text: Define the domain of $s(x)=\frac{x+29}{(x-6)(x+7)}$. Use interval notation for your answer. The domain of $s(x)$ is: $\square$
failed

Solution

failed
failed

Solution Steps

To find the domain of the function \( s(x) = \frac{x+29}{(x-6)(x+7)} \), we need to determine the values of \( x \) for which the function is defined. The function is undefined where the denominator is zero. Therefore, we need to find the values of \( x \) that make \( (x-6)(x+7) = 0 \) and exclude them from the domain.

Step 1: Identify the Function

We are given the function \( s(x) = \frac{x + 29}{(x - 6)(x + 7)} \). To determine the domain, we need to find the values of \( x \) that make the denominator zero.

Step 2: Find the Zeros of the Denominator

The denominator is given by \( (x - 6)(x + 7) \). Setting this equal to zero, we solve: \[ (x - 6)(x + 7) = 0 \] This gives us the solutions: \[ x - 6 = 0 \quad \Rightarrow \quad x = 6 \] \[ x + 7 = 0 \quad \Rightarrow \quad x = -7 \]

Step 3: Determine the Domain

The function \( s(x) \) is undefined at \( x = 6 \) and \( x = -7 \). Therefore, we exclude these points from the domain. The domain in interval notation is: \[ (-\infty, -7) \cup (-7, 6) \cup (6, \infty) \]

Final Answer

The domain of \( s(x) \) is \(\boxed{(-\infty, -7) \cup (-7, 6) \cup (6, \infty)}\).

Was this solution helpful?
failed
Unhelpful
failed
Helpful