Questions: Subtract. 9 3/5 - 7 1/3 9 3/5 - 7 1/3 = (Type a whole number, proper fraction, or mixed number. Simplify your answer.)

Solution Steps

Convert \( 9 \frac{3}{5} \) and \( 7 \frac{1}{3} \) to improper fractions: \[ 9 \frac{3}{5} = \frac{9 \times 5 + 3}{5} = \frac{48}{5} \] \[ 7 \frac{1}{3} = \frac{7 \times 3 + 1}{3} = \frac{22}{3} \]

The least common multiple of the denominators \( 5 \) and \( 3 \) is \( 15 \). Convert both fractions to have this common denominator: \[ \frac{48}{5} = \frac{48 \times 3}{5 \times 3} = \frac{144}{15} \] \[ \frac{22}{3} = \frac{22 \times 5}{3 \times 5} = \frac{110}{15} \]

Now, subtract the two improper fractions: \[ \frac{144}{15} - \frac{110}{15} = \frac{144 - 110}{15} = \frac{34}{15} \]

The fraction \( \frac{34}{15} \) is already in its simplest form. Convert it back to a mixed number: \[ 34 \div 15 = 2 \quad \text{(whole number)} \] \[ 34 \mod 15 = 4 \quad \text{(remainder)} \] Thus, the mixed number is \( 2 \frac{4}{15} \).

Final Answer