Questions: Rewrite each of the following equations: (a) Rewrite 2^4=16 as a logarithmic equation: (b) Rewrite log 0.0001=-4 as an exponential equation:

Rewrite each of the following equations:
(a) Rewrite 2^4=16 as a logarithmic equation: 
(b) Rewrite log 0.0001=-4 as an exponential equation:
Transcript text: Rewrite each of the following equations: (a) Rewrite $2^{4}=16$ as a logarithmic equation: $\square$ (b) Rewrite $\log 0.0001=-4$ as an exponential equation: $\square$
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Solution

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Solution Steps

Step 1: Rewrite \(2^{4}=16\) as a logarithmic equation

The exponential equation \(2^{4}=16\) can be rewritten in logarithmic form using the definition of logarithms:
If \(a^{b}=c\), then \(\log_{a}c = b\).
Applying this to \(2^{4}=16\), we get:
\(\log_{2}16 = 4\).

Step 2: Rewrite \(\log 0.0001=-4\) as an exponential equation

The logarithmic equation \(\log 0.0001=-4\) can be rewritten in exponential form using the definition of logarithms:
If \(\log_{a}c = b\), then \(a^{b}=c\).
Here, the base \(a\) is \(10\) (since no base is specified, it is assumed to be \(10\)).
Applying this to \(\log 0.0001=-4\), we get:
\(10^{-4}=0.0001\).

Final Answer

(a) \( \boxed{\log_{2}16 = 4} \)
(b) \( \boxed{10^{-4} = 0.0001} \)

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