The probability that the observation or mean of a sample falls within the specified range is approximately 0.267.
Given $n = 16$, the distribution of sample means is approximately normal with mean $\mu_{\bar{x}} = 1.3$ and standard deviation $\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} = 1.1$.
Using the formula $Z = \frac{\bar{X} - \mu_{\bar{x}}}{\sigma_{\bar{x}}}$, convert the range values to Z-scores.
For the lower bound 0, $Z_1 = \frac{0 - 1.3}{1.1} = -1.182$.
For the upper bound 3, $Z_2 = \frac{3 - 1.3}{1.1} = 1.546$.
Using Z-tables or software, find the probability for $Z_1$ and $Z_2$. The probability that the mean of a sample falls within the specified range is $P(Z_1 < Z < Z_2) = P(Z < Z_2) - P(Z < Z_1) = 0.82$.
The probability that the observation or mean of a sample falls within the specified range is approximately 0.82.