Questions: Question 2 (1 point) (18.5) Which of the following is the reaction for the acid hydrolysis of N methylacetamide? CH3-C-NH-C-CH3+H2O -> CH3-C-NH2+CH3OH

Question 2 (1 point)
(18.5) Which of the following is the reaction for the acid hydrolysis of N methylacetamide?
CH3-C-NH-C-CH3+H2O -> CH3-C-NH2+CH3OH

Transcript text: Question 2 (1 point) (18.5) Which of the following is the reaction for the acid hydrolysis of N methylacetamide? $\mathrm{CH}_{3}-\stackrel{\mathrm{I}}{\mathrm{C}}-\mathrm{NH}_{\mathrm{C}}-\mathrm{CH}_{3}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{CH}_{3}-\stackrel{\mathrm{II}}{\mathrm{C}}-\mathrm{NH}_{2}+\mathrm{CH}_{3} \mathrm{OH}$

Solution

Solution Steps

Step 1: Identify the reactants and products

The reactants are N-methylacetamide (CH3-C(=O)-NH-CH3), water (H2O), and hydrochloric acid (HCl). The products are acetic acid (CH3-C(=O)-NH3+) and methanol (CH3OH).

Step 2: Write the balanced chemical equation

CH3-C(=O)-NH-CH3 + H2O + HCl → CH3-C(=O)-NH3+Cl- + CH3OH