Questions: 4x^2 + 9y^2 ≤ 36

4x^2 + 9y^2 ≤ 36
Transcript text: $4 x^{2}+9 y^{2} \leq 36$
failed

Solution

failed
failed

Solution Steps

Step 1: Identify the Type of Inequality

The given inequality is \(4x^{2} + 9y^{2} \leq 36\). This is an inequality representing an ellipse centered at the origin.

Step 2: Rewrite the Inequality in Standard Form

To rewrite the inequality in standard form, divide every term by 36:

\[ \frac{4x^{2}}{36} + \frac{9y^{2}}{36} \leq 1 \]

Simplify the fractions:

\[ \frac{x^{2}}{9} + \frac{y^{2}}{4} \leq 1 \]

Step 3: Identify the Characteristics of the Ellipse

The standard form of an ellipse is \(\frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} \leq 1\), where \(a\) and \(b\) are the semi-major and semi-minor axes, respectively.

From \(\frac{x^{2}}{9} + \frac{y^{2}}{4} \leq 1\), we identify:

  • \(a^{2} = 9\) so \(a = 3\)
  • \(b^{2} = 4\) so \(b = 2\)

This means the ellipse is centered at the origin with a semi-major axis of 3 along the x-axis and a semi-minor axis of 2 along the y-axis.

Final Answer

The inequality \(4x^{2} + 9y^{2} \leq 36\) represents an ellipse centered at the origin with a semi-major axis of 3 along the x-axis and a semi-minor axis of 2 along the y-axis. The standard form of the inequality is:

\[ \boxed{\frac{x^{2}}{9} + \frac{y^{2}}{4} \leq 1} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful