We are given that the point (6,10)(6, 10)(6,10) lies on the graph of y=f(x)y = f(x)y=f(x). This means that when x=6x = 6x=6, f(x)=10f(x) = 10f(x)=10. Mathematically, this is written as: f(6)=10. f(6) = 10. f(6)=10.
We are asked to find a point on the graph of y=12f(x)y = \frac{1}{2 f(x)}y=2f(x)1. Using the value of f(6)=10f(6) = 10f(6)=10, substitute x=6x = 6x=6 into the new function: y=12f(6)=12⋅10=120. y = \frac{1}{2 f(6)} = \frac{1}{2 \cdot 10} = \frac{1}{20}. y=2f(6)1=2⋅101=201.
The corresponding point on the graph of y=12f(x)y = \frac{1}{2 f(x)}y=2f(x)1 is (6,120)(6, \frac{1}{20})(6,201).
(6,120) \boxed{\left(6, \frac{1}{20}\right)} (6,201)
Oops, Image-based questions are not yet availableUse Solvely.ai for full features.
Failed. You've reached the daily limit for free usage.Please come back tomorrow or visit Solvely.ai for additional homework help.