Questions: What is a linear equation? ∛(x)-3=y 2x-4y-6=0 -√x y=12 2x=y^2

What is a linear equation?
∛(x)-3=y
2x-4y-6=0
-√x y=12
2x=y^2
Transcript text: What is a linear equation? $\sqrt[3]{(x)}-3=y$ $2 x-4 y-6=0$ $-\sqrt{x} y=12$ $2 x=y^{2}$
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Solution

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Solution Steps

To determine whether each equation is a linear equation, we need to check if the equation can be written in the form \( ax + by + c = 0 \), where \( a \), \( b \), and \( c \) are constants, and \( x \) and \( y \) are variables. A linear equation should not have variables raised to any power other than 1, nor should it involve roots or products of variables.

Step 1: Analyze the First Equation

The first equation is \( \sqrt[3]{(x)} - 3 = y \). This equation contains a cube root of \( x \), which is a non-linear term. Therefore, it is not a linear equation.

Step 2: Analyze the Second Equation

The second equation is \( 2x - 4y - 6 = 0 \). This equation can be rearranged to the standard form \( ax + by + c = 0 \) with \( a = 2 \), \( b = -4 \), and \( c = -6 \). Since it contains only linear terms, it is a linear equation.

Step 3: Analyze the Third Equation

The third equation is \( -\sqrt{x}y = 12 \). This equation includes a square root of \( x \), which makes it non-linear. Thus, it is not a linear equation.

Step 4: Analyze the Fourth Equation

The fourth equation is \( 2x = y^2 \). This equation contains \( y^2 \), which is a quadratic term, indicating that it is also non-linear.

Final Answer

The results of the analysis are as follows:

  1. \( \sqrt[3]{(x)} - 3 = y \) is not linear.
  2. \( 2x - 4y - 6 = 0 \) is linear.
  3. \( -\sqrt{x}y = 12 \) is not linear.
  4. \( 2x = y^2 \) is not linear.

Thus, the final answers are:

  • For the first equation: \(\boxed{\text{not linear}}\)
  • For the second equation: \(\boxed{\text{linear}}\)
  • For the third equation: \(\boxed{\text{not linear}}\)
  • For the fourth equation: \(\boxed{\text{not linear}}\)
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