Questions: What is the mass of (4.50 times 10^22) formula units of (mathrmCoSO4) ? (CoSO4, (154.99 mathrm~g / mathrmmol) ) [?] mathrmg mathrmCoSO4]

What is the mass of (4.50 times 10^22) formula units of (mathrmCoSO4) ? (CoSO4, (154.99 mathrm~g / mathrmmol) ) [?] mathrmg mathrmCoSO4]
Transcript text: What is the mass of $4.50 \times 10^{22}$ formula units of $\mathrm{CoSO}_{4}$ ? (CoSO4, $154.99 \mathrm{~g} / \mathrm{mol}$ ) [?] $\mathrm{g} \mathrm{CoSO}_{4}$
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Solution

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Solution Steps

Step 1: Determine the number of moles of $\mathrm{CoSO}_{4}$

To find the number of moles, we use Avogadro's number, which is \(6.022 \times 10^{23}\) formula units per mole. The number of moles \(n\) is given by:

\[ n = \frac{\text{number of formula units}}{\text{Avogadro's number}} = \frac{4.50 \times 10^{22}}{6.022 \times 10^{23}} \]

Step 2: Calculate the number of moles

Perform the division to find the number of moles:

\[ n = \frac{4.50 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0747 \text{ moles} \]

Step 3: Calculate the mass of $\mathrm{CoSO}_{4}$

The mass \(m\) of $\mathrm{CoSO}_{4}$ can be found using the molar mass and the number of moles:

\[ m = n \times \text{molar mass} = 0.0747 \text{ moles} \times 154.99 \text{ g/mol} \]

Step 4: Perform the multiplication

Calculate the mass:

\[ m \approx 0.0747 \times 154.99 \approx 11.58 \text{ g} \]

Final Answer

\(\boxed{11.58 \text{ g}}\)

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