Questions: What is the mass of (4.50 times 10^22) formula units of (mathrmCoSO4) ? (CoSO4, (154.99 mathrm~g / mathrmmol) ) [?] mathrmg mathrmCoSO4]

Solution Steps

To find the number of moles, we use Avogadro's number, which is \(6.022 \times 10^{23}\) formula units per mole. The number of moles \(n\) is given by:

\[ n = \frac{\text{number of formula units}}{\text{Avogadro's number}} = \frac{4.50 \times 10^{22}}{6.022 \times 10^{23}} \]

Perform the division to find the number of moles:

\[ n = \frac{4.50 \times 10^{22}}{6.022 \times 10^{23}} \approx 0.0747 \text{ moles} \]

The mass \(m\) of $\mathrm{CoSO}_{4}$ can be found using the molar mass and the number of moles:

\[ m = n \times \text{molar mass} = 0.0747 \text{ moles} \times 154.99 \text{ g/mol} \]

Calculate the mass:

\[ m \approx 0.0747 \times 154.99 \approx 11.58 \text{ g} \]

Final Answer