To solve the equation \( e^{7x} = 12 \), we first take the natural logarithm of both sides:
\[ \ln(e^{7x}) = \ln(12) \]
Using the property of logarithms that states \( \ln(e^y) = y \), we simplify the left side:
\[ 7x = \ln(12) \]
Next, we isolate \( x \) by dividing both sides by 7:
\[ x = \frac{\ln(12)}{7} \]
Calculating the value of \( \ln(12) \) gives approximately \( 2.4849 \). Thus, we have:
\[ x \approx \frac{2.4849}{7} \approx 0.3549 \]
\[ \boxed{x \approx 0.3549} \]
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