Questions: Question 6 Convert the angle 309.18666666667° to degrees/minutes/seconds form. Question 7 Subtract the two angles in degrees/minutes/seconds form. 70° 49′ 47″ - 246° 59′ 36″ Question 8

Question 6

Convert the angle 309.18666666667° to degrees/minutes/seconds form.

Question 7

Subtract the two angles in degrees/minutes/seconds form.
70° 49′ 47″ - 246° 59′ 36″

Question 8
Transcript text: Question 6 1 pt 1 Details Convert the angle $309.18666666667^{\circ}$ to degrees/minutes/seconds form. $\square$ , $\square$ $\square$ Question 7 1 pt 1 Details Subtract the two angles in degrees/minutes/seconds form. $70^{\circ} 49^{\prime} 47^{\prime \prime}-246^{\circ} 59^{\prime} 36^{\prime \prime}$ $\square$ - $\square$ $\square$ I Question 8 1 pt 1 Details
failed

Solution

failed
failed

Solution Steps

Solution Approach

For Question 6:

  1. Separate the integer part (degrees) from the decimal part.
  2. Convert the decimal part to minutes by multiplying by 60.
  3. Separate the integer part of the minutes and convert the remaining decimal part to seconds by multiplying by 60.

For Question 7:

  1. Convert both angles to seconds.
  2. Subtract the second angle's total seconds from the first angle's total seconds.
  3. Convert the result back to degrees, minutes, and seconds.
Step 1: Convert \( 309.18666666667^{\circ} \) to Degrees, Minutes, and Seconds

To convert the angle \( 309.18666666667^{\circ} \):

  • The integer part (degrees) is \( 309 \).
  • The decimal part is \( 0.18666666667 \).
  • Convert the decimal part to minutes: \[ 0.18666666667 \times 60 \approx 11.2000000002 \implies 11 \text{ minutes} \]
  • Convert the remaining decimal part to seconds: \[ 0.2000000002 \times 60 \approx 12.0000000121 \implies 12.00 \text{ seconds} \] Thus, \( 309.18666666667^{\circ} \) is equivalent to \( 309^{\circ} 11' 12.00'' \).
Step 2: Subtract the Angles in Degrees, Minutes, and Seconds

To subtract \( 70^{\circ} 49' 47'' \) from \( 246^{\circ} 59' 36'' \):

  • Convert both angles to total seconds: \[ \text{Total seconds for } 70^{\circ} 49' 47'' = 70 \times 3600 + 49 \times 60 + 47 = 254987 \text{ seconds} \] \[ \text{Total seconds for } 246^{\circ} 59' 36'' = 246 \times 3600 + 59 \times 60 + 36 = 889176 \text{ seconds} \]
  • Subtract the second angle from the first: \[ 254987 - 889176 = -634189 \text{ seconds} \]
  • Convert the result back to degrees, minutes, and seconds: \[ \text{Degrees} = \left\lfloor \frac{-634189}{3600} \right\rfloor = -177 \] \[ \text{Remaining seconds} = -634189 \mod 3600 = 3011 \] \[ \text{Minutes} = \left\lfloor \frac{3011}{60} \right\rfloor = 50 \] \[ \text{Seconds} = 3011 \mod 60 = 11 \] Thus, the result of the subtraction is \( -177^{\circ} 50' 11'' \).

Final Answer

The final answers are:

  • For the conversion: \( 309^{\circ} 11' 12.00'' \)
  • For the subtraction: \( -177^{\circ} 50' 11'' \)

\[ \boxed{309^{\circ} 11' 12.00''} \] \[ \boxed{-177^{\circ} 50' 11''} \]

Was this solution helpful?
failed
Unhelpful
failed
Helpful