To prove that \( f(x) \) and \( g(x) \) are inverses both algebraically and graphically, we need to follow these steps:
Algebraic Proof:
Graphical Proof:
To prove that \( f(x) \) and \( g(x) \) are inverses algebraically, we need to show that \( f(g(x)) = x \) and \( g(f(x)) = x \).
Given: \[ f(x) = \frac{4}{x} - 2 \] \[ g(x) = \frac{4}{x+2} \]
Substitute \( g(x) \) into \( f(x) \): \[ f(g(x)) = f\left( \frac{4}{x+2} \right) \] \[ f\left( \frac{4}{x+2} \right) = \frac{4}{\frac{4}{x+2}} - 2 \] \[ = \frac{4(x+2)}{4} - 2 \] \[ = x + 2 - 2 \] \[ = x \]
Thus, \( f(g(x)) = x \).
Substitute \( f(x) \) into \( g(x) \): \[ g(f(x)) = g\left( \frac{4}{x} - 2 \right) \] \[ g\left( \frac{4}{x} - 2 \right) = \frac{4}{\left( \frac{4}{x} - 2 \right) + 2} \] \[ = \frac{4}{\frac{4}{x}} \] \[ = \frac{4x}{4} \] \[ = x \]
Thus, \( g(f(x)) = x \).
Since both \( f(g(x)) = x \) and \( g(f(x)) = x \), we have shown algebraically that \( f(x) \) and \( g(x) \) are inverses.
To verify graphically, we need to plot both functions and check if they are reflections of each other across the line \( y = x \).
Plot \( f(x) = \frac{4}{x} - 2 \):
Plot \( g(x) = \frac{4}{x+2} \):
By plotting these functions, we can visually confirm that \( f(x) \) and \( g(x) \) are reflections of each other across the line \( y = x \).
\[ \boxed{f(x) = \frac{4}{x} - 2 \text{ and } g(x) = \frac{4}{x+2} \text{ are inverses.}} \]
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