Questions: Hemophilia A is an X-linked recessive disorder. What is the probability that a son will have hemophilia if the parents are a normal man and a woman who is a carrier?
Transcript text: Hemophilia $A$ is an $X$-linked recessive disorder. What is the probability that a son will have hemophilia if the parents are a normal man and a woman who is a carrier?
Solution
The answer is the first one: 50%.
Explanation for each option:
50%: This is correct. Hemophilia A is an X-linked recessive disorder. A normal man has an XY genotype, and a carrier woman has an X\(^H\)X\(^h\) genotype (where X\(^H\) is the normal allele and X\(^h\) is the hemophilia allele). The possible combinations for their son (who inherits the Y chromosome from his father and one of the X chromosomes from his mother) are X\(^H\)Y (normal) and X\(^h\)Y (hemophilia). Therefore, there is a 50% chance that the son will inherit the X\(^h\) chromosome and have hemophilia.
25%: This is incorrect. The probability of a son having hemophilia is not 25%.
0%: This is incorrect. There is a chance that the son could inherit the hemophilia allele.
100%: This is incorrect. Not all sons will inherit the hemophilia allele; there is only a 50% chance.
75%: This is incorrect. The probability of a son having hemophilia is not 75%.
Summary:
The probability that a son will have hemophilia if the parents are a normal man and a woman who is a carrier is 50%.