To solve the given expression, first calculate the product of the fractions \(\frac{1}{4}\) and \(\frac{1}{5}\). Then, add the result to \(\frac{1}{9}\).
Step 1: Calculate the Product
First, we calculate the product of the fractions \( \frac{1}{4} \) and \( \frac{1}{5} \):
\[
\frac{1}{4} \cdot \frac{1}{5} = \frac{1 \cdot 1}{4 \cdot 5} = \frac{1}{20}
\]
Step 2: Add to \( \frac{1}{9} \)
Next, we add the result from Step 1 to \( \frac{1}{9} \):
\[
\frac{1}{9} + \frac{1}{20}
\]
To perform this addition, we need a common denominator. The least common multiple of 9 and 20 is 180. We convert each fraction:
\[
\frac{1}{9} = \frac{20}{180} \quad \text{and} \quad \frac{1}{20} = \frac{9}{180}
\]
Now we can add them:
\[
\frac{20}{180} + \frac{9}{180} = \frac{20 + 9}{180} = \frac{29}{180}
\]
Final Answer
The final result of the expression \( \frac{1}{9} + \frac{1}{4} \cdot \frac{1}{5} \) is
\[
\boxed{\frac{29}{180}}
\]