Questions: If the product of (5x-6) and (x+1) is written in standard form, what will the middle term be?
-1
Transcript text: If the product of $(5 x-6)$ and $(x+1)$ is written in standard form, what will the middle term be?
\[
-1
\]
Solution
Solution Steps
To find the middle term of the product of \((5x - 6)\) and \((x + 1)\), we need to expand the expression using the distributive property (also known as the FOIL method for binomials). The middle term will be the sum of the products of the outer and inner terms.
Step 1: Expand the Expression
We start with the expression \((5x - 6)(x + 1)\). Using the distributive property, we expand it as follows:
\[
(5x - 6)(x + 1) = 5x \cdot x + 5x \cdot 1 - 6 \cdot x - 6 \cdot 1
\]
This simplifies to:
\[
5x^2 + 5x - 6x - 6
\]
Step 2: Combine Like Terms
Next, we combine the like terms in the expanded expression:
\[
5x^2 + (5x - 6x) - 6 = 5x^2 - x - 6
\]
Step 3: Identify the Middle Term
In the standard form \(ax^2 + bx + c\), the middle term corresponds to the coefficient of \(x\). From our expression \(5x^2 - x - 6\), the coefficient of \(x\) is \(-1\).