Questions: 17. Find the volume (in mL ) occupied by a 4.3 g sample of benzene. (The specific gravity of benzene is 0.880 )

Solution Steps

We need to find the volume occupied by a 4.3 g sample of benzene, given that the specific gravity of benzene is 0.880.

Specific gravity is the ratio of the density of a substance to the density of water. Since the density of water is $1 \, \text{g/mL}$, the density of benzene can be calculated as: $$\text{Density of benzene} = \text{Specific gravity of benzene} \times \text{Density of water}$$ $$\text{Density of benzene} = 0.880 \times 1 \, \text{g/mL} = 0.880 \, \text{g/mL}$$

The formula for density is: $$\text{Density} = \frac{\text{Mass}}{\text{Volume}}$$ Rearranging to solve for volume: $$\text{Volume} = \frac{\text{Mass}}{\text{Density}}$$ Substitute the given mass and the calculated density: $$\text{Volume} = \frac{4.3 \, \text{g}}{0.880 \, \text{g/mL}}$$

Perform the division: $$\text{Volume} = \frac{4.3}{0.880} \approx 4.8864 \, \text{mL}$$

Final Answer