Questions: Using your graphing calculator, determine the interval for which the following function positive and determine the interval for which this function is increasing. f(x) = 2x^3 - 6x^2 - 26x + 30 Set the window to the following values: x Min = -10, x Max = 10, y Min = -100, y Max = 100 The interval for which this function is positive is: . U The interval for which this function is increasing is: U To enter infinity or negative infinity type inf or -inf in the blank. For decimal answers round to the nearest tenth (Eg: 1.7)

Using your graphing calculator, determine the interval for which the following function positive and determine the interval for which this function is increasing.

f(x) = 2x^3 - 6x^2 - 26x + 30

Set the window to the following values:

x Min = -10, x Max = 10, y Min = -100, y Max = 100

The interval for which this function is positive is: . U 

The interval for which this function is increasing is: 
U 

To enter infinity or negative infinity type inf or -inf in the blank.

For decimal answers round to the nearest tenth (Eg: 1.7)
Transcript text: Using your graphing calculator, determine the interval for which the following function positive and determine the interval for which this function is increasing. \[ f(x)=2 x^{3}-6 x^{2}-26 x+30 \] Set the window to the following values: \[ x \operatorname{Min}=-10 \quad x \operatorname{Max}=10 \quad y \operatorname{Min}=-100 \quad y \operatorname{Max}=100 \] The interval for which this function is positive is: $\square$ . $\square$ U $\square$ $\square$ ) The interval for which this function is increasing is: $\square$ $\square$ U $\square$ $\square$ To enter infinity or negative infinity type inf or -inf in the blank. For decimal answers round to the nearest tenth (Eg: 1.7)
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Solution

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Solution Steps

Step 1: Find the Roots of the Function

To determine where the function \( f(x) = 2x^3 - 6x^2 - 26x + 30 \) is positive, we first find its roots by solving the equation \( f(x) = 0 \). The roots are \( x = -3 \), \( x = 1 \), and \( x = 5 \).

Step 2: Find the Derivative of the Function

Next, we compute the derivative of the function, given by \( f'(x) = 6x^2 - 12x - 26 \). This derivative will help us identify the critical points where the function may change from increasing to decreasing or vice versa.

Step 3: Find the Critical Points

We set the derivative equal to zero to find the critical points: \[ 6x^2 - 12x - 26 = 0 \] Solving this equation yields the critical points \( x = -1.3094010767585031 \) and \( x = 3.309401076758503 \).

Step 4: Determine Intervals of Positivity

To find the intervals where the function is positive, we evaluate the sign of \( f(x) \) in the intervals defined by the roots:

  • For the interval \( (-\infty, -3) \)
  • For the interval \( (-3, 1) \)
  • For the interval \( (1, 5) \)
  • For the interval \( (5, \infty) \)

The function is positive in the interval \( (-3, 1) \).

Step 5: Determine Intervals of Increase

To find the intervals where the function is increasing, we evaluate the sign of \( f'(x) \) in the intervals defined by the critical points:

  • For the interval \( (-\infty, -1.3094010767585031) \)
  • For the interval \( (-1.3094010767585031, 3.309401076758503) \)
  • For the interval \( (3.309401076758503, \infty) \)

Since there are no intervals where \( f'(x) > 0 \), the function does not have any intervals of increase.

Summary of Results
  • The function \( f(x) \) is positive in the interval \( (-3, 1) \).
  • The function \( f(x) \) is not increasing in any interval.

Final Answer

The interval for which this function is positive is: \( \boxed{(-3, 1)} \).

The interval for which this function is increasing is: \( \boxed{\text{none}} \).

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