Questions: Using your graphing calculator, determine the interval for which the following function positive and determine the interval for which this function is increasing.
f(x) = 2x^3 - 6x^2 - 26x + 30
Set the window to the following values:
x Min = -10, x Max = 10, y Min = -100, y Max = 100
The interval for which this function is positive is: . U
The interval for which this function is increasing is:
U
To enter infinity or negative infinity type inf or -inf in the blank.
For decimal answers round to the nearest tenth (Eg: 1.7)
Transcript text: Using your graphing calculator, determine the interval for which the following function positive and determine the interval for which this function is increasing.
\[
f(x)=2 x^{3}-6 x^{2}-26 x+30
\]
Set the window to the following values:
\[
x \operatorname{Min}=-10 \quad x \operatorname{Max}=10 \quad y \operatorname{Min}=-100 \quad y \operatorname{Max}=100
\]
The interval for which this function is positive is: $\square$ . $\square$ U $\square$
$\square$ )
The interval for which this function is increasing is: $\square$
$\square$ U $\square$
$\square$
To enter infinity or negative infinity type inf or -inf in the blank.
For decimal answers round to the nearest tenth (Eg: 1.7)
Solution
Solution Steps
Step 1: Find the Roots of the Function
To determine where the function \( f(x) = 2x^3 - 6x^2 - 26x + 30 \) is positive, we first find its roots by solving the equation \( f(x) = 0 \). The roots are \( x = -3 \), \( x = 1 \), and \( x = 5 \).
Step 2: Find the Derivative of the Function
Next, we compute the derivative of the function, given by \( f'(x) = 6x^2 - 12x - 26 \). This derivative will help us identify the critical points where the function may change from increasing to decreasing or vice versa.
Step 3: Find the Critical Points
We set the derivative equal to zero to find the critical points:
\[
6x^2 - 12x - 26 = 0
\]
Solving this equation yields the critical points \( x = -1.3094010767585031 \) and \( x = 3.309401076758503 \).
Step 4: Determine Intervals of Positivity
To find the intervals where the function is positive, we evaluate the sign of \( f(x) \) in the intervals defined by the roots:
For the interval \( (-\infty, -3) \)
For the interval \( (-3, 1) \)
For the interval \( (1, 5) \)
For the interval \( (5, \infty) \)
The function is positive in the interval \( (-3, 1) \).
Step 5: Determine Intervals of Increase
To find the intervals where the function is increasing, we evaluate the sign of \( f'(x) \) in the intervals defined by the critical points:
For the interval \( (-\infty, -1.3094010767585031) \)
For the interval \( (-1.3094010767585031, 3.309401076758503) \)
For the interval \( (3.309401076758503, \infty) \)
Since there are no intervals where \( f'(x) > 0 \), the function does not have any intervals of increase.
Summary of Results
The function \( f(x) \) is positive in the interval \( (-3, 1) \).
The function \( f(x) \) is not increasing in any interval.
Final Answer
The interval for which this function is positive is: \( \boxed{(-3, 1)} \).
The interval for which this function is increasing is: \( \boxed{\text{none}} \).