To solve the system of equations by substitution, we can follow these steps:
First, we solve the first equation for \( y \): \[ -3x + y = 19 \implies y = 3x + 19 \]
Next, we substitute \( y = 3x + 19 \) into the second equation: \[ 2x - 3(3x + 19) = -1 \] Simplify and solve for \( x \): \[ 2x - 9x - 57 = -1 \implies -7x - 57 = -1 \implies -7x = 56 \implies x = -8 \]
Now, substitute \( x = -8 \) back into the expression \( y = 3x + 19 \): \[ y = 3(-8) + 19 = -24 + 19 = -5 \]
\(\boxed{(x, y) = (-8, -5)}\)
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