From the graph, we can identify two points on the line. Let's choose the points (−3,−2)(-3, -2)(−3,−2) and (3,2)(3, 2)(3,2).
The slope mmm of a line passing through two points (x1,y1)(x_1, y_1)(x1,y1) and (x2,y2)(x_2, y_2)(x2,y2) is given by: m=y2−y1x2−x1 m = \frac{y_2 - y_1}{x_2 - x_1} m=x2−x1y2−y1
Substitute the coordinates of the points (−3,−2)(-3, -2)(−3,−2) and (3,2)(3, 2)(3,2) into the slope formula: m=2−(−2)3−(−3)=2+23+3=46=23 m = \frac{2 - (-2)}{3 - (-3)} = \frac{2 + 2}{3 + 3} = \frac{4}{6} = \frac{2}{3} m=3−(−3)2−(−2)=3+32+2=64=32
The slope of the line is 23\frac{2}{3}32.
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