Questions: Suppose that y is proportional to the 4th power of x, and that y=17 when x=6. What is y when x=4? Round your answer to two decimal places if necessary.
Transcript text: Suppose that $y$ is proportional to the $4^{\text {th }}$ power of $x$, and that $y=17$ when $x=6$. What is $y$ when $x=4$ ? Round your answer to two decimal places if necessary.
Solution
Solution Steps
To solve this problem, we need to use the concept of direct proportionality. Since \( y \) is proportional to the \( 4^{\text{th}} \) power of \( x \), we can write the relationship as \( y = k \cdot x^4 \), where \( k \) is the proportionality constant. First, we will find the value of \( k \) using the given values of \( y \) and \( x \). Then, we will use this value of \( k \) to find \( y \) when \( x = 4 \).
Solution Approach
Use the given values \( y = 17 \) and \( x = 6 \) to find the proportionality constant \( k \).
Substitute \( x = 4 \) into the equation \( y = k \cdot x^4 \) to find the new value of \( y \).
Step 1: Establish the Proportional Relationship
Given that \( y \) is proportional to the \( 4^{\text{th}} \) power of \( x \), we can express this relationship mathematically as:
\[
y = k \cdot x^4
\]
where \( k \) is the proportionality constant.
Step 2: Calculate the Proportionality Constant
Using the provided values \( y = 17 \) when \( x = 6 \), we can substitute these values into the equation to find \( k \):
\[
17 = k \cdot 6^4
\]
Calculating \( 6^4 \):
\[
6^4 = 1296
\]
Thus, we have:
\[
k = \frac{17}{1296} \approx 0.013117283950617283
\]
Step 3: Find \( y \) when \( x = 4 \)
Now, we substitute \( x = 4 \) into the equation to find the new value of \( y \):
\[
y = k \cdot 4^4
\]
Calculating \( 4^4 \):
\[
4^4 = 256
\]
Substituting \( k \) into the equation:
\[
y = 0.013117283950617283 \cdot 256 \approx 3.3580246913580245
\]
Rounding this value to four significant digits gives:
\[
y \approx 3.36
\]
Final Answer
Thus, the value of \( y \) when \( x = 4 \) is \(\boxed{3.36}\).