Questions: На рис. 38 K L M N- прямоугольник, угол C=90°, AC=BC, KL:LM=2:5, PKLMN=56 см. Найдите AB.
Transcript text: На рис. $38 K L M N-$ прямоугольник, $\angle C=90^{\circ}, A C=B C$, $K L: L M=2: 5, P_{K L M N}=56 \mathrm{~cm}$. Найдите $A B$.
Solution
Solution Steps
Step 1: Understand the Problem
We are given a right triangle \( \triangle KLMN \) with \( \angle C = 90^\circ \), \( AC = BC \), \( KL:LM = 2:5 \), and the perimeter \( P_{KLMN} = 56 \) cm. We need to find the length of \( AB \).
Step 2: Identify Key Relationships
Since \( \angle C = 90^\circ \) and \( AC = BC \), \( \triangle ABC \) is an isosceles right triangle. This implies \( AC = BC = x \) and \( AB = x\sqrt{2} \).
Step 3: Use Given Ratios
Given \( KL:LM = 2:5 \), let \( KL = 2k \) and \( LM = 5k \). The perimeter of \( \triangle KLMN \) is the sum of all sides:
\[ KL + LM + MN + NK = 56 \]
Step 4: Calculate the Perimeter
Since \( \triangle KLMN \) is a right triangle, we can use the Pythagorean theorem:
\[ KL^2 + LM^2 = KN^2 \]
\[ (2k)^2 + (5k)^2 = KN^2 \]
\[ 4k^2 + 25k^2 = KN^2 \]
\[ 29k^2 = KN^2 \]
\[ KN = \sqrt{29}k \]
To simplify \( k \), rationalize the denominator:
\[ k = \frac{56(8 - \sqrt{29})}{(8 + \sqrt{29})(8 - \sqrt{29})} \]
\[ k = \frac{56(8 - \sqrt{29})}{64 - 29} \]
\[ k = \frac{56(8 - \sqrt{29})}{35} \]
\[ k = \frac{56}{35}(8 - \sqrt{29}) \]
\[ k = \frac{8}{5}(8 - \sqrt{29}) \]
Step 7: Calculate \( AB \)
Since \( AC = BC = x \) and \( AB = x\sqrt{2} \), we need to find \( x \). Given \( AC = BC \) and the perimeter of \( \triangle ABC \) is \( 56 \) cm, we can use the relationship:
\[ AC + BC + AB = 56 \]
\[ x + x + x\sqrt{2} = 56 \]
\[ 2x + x\sqrt{2} = 56 \]
\[ x(2 + \sqrt{2}) = 56 \]
\[ x = \frac{56}{2 + \sqrt{2}} \]
Step 8: Simplify \( x \)
Rationalize the denominator:
\[ x = \frac{56(2 - \sqrt{2})}{(2 + \sqrt{2})(2 - \sqrt{2})} \]
\[ x = \frac{56(2 - \sqrt{2})}{4 - 2} \]
\[ x = \frac{56(2 - \sqrt{2})}{2} \]
\[ x = 28(2 - \sqrt{2}) \]
Final Answer
\[ AB = x\sqrt{2} = 28(2 - \sqrt{2})\sqrt{2} \]
\[ AB = 28(2\sqrt{2} - 2) \]
\[ AB = 56\sqrt{2} - 56 \]
Thus, the length of \( AB \) is \( 56\sqrt{2} - 56 \) cm.