Questions: На рис. 38 K L M N- прямоугольник, угол C=90°, AC=BC, KL:LM=2:5, PKLMN=56 см. Найдите AB.

На рис. 38 K L M N- прямоугольник, угол C=90°, AC=BC, KL:LM=2:5, PKLMN=56 см. Найдите AB.
Transcript text: На рис. $38 K L M N-$ прямоугольник, $\angle C=90^{\circ}, A C=B C$, $K L: L M=2: 5, P_{K L M N}=56 \mathrm{~cm}$. Найдите $A B$.
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Solution

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Solution Steps

Step 1: Understand the Problem

We are given a right triangle \( \triangle KLMN \) with \( \angle C = 90^\circ \), \( AC = BC \), \( KL:LM = 2:5 \), and the perimeter \( P_{KLMN} = 56 \) cm. We need to find the length of \( AB \).

Step 2: Identify Key Relationships

Since \( \angle C = 90^\circ \) and \( AC = BC \), \( \triangle ABC \) is an isosceles right triangle. This implies \( AC = BC = x \) and \( AB = x\sqrt{2} \).

Step 3: Use Given Ratios

Given \( KL:LM = 2:5 \), let \( KL = 2k \) and \( LM = 5k \). The perimeter of \( \triangle KLMN \) is the sum of all sides: \[ KL + LM + MN + NK = 56 \]

Step 4: Calculate the Perimeter

Since \( \triangle KLMN \) is a right triangle, we can use the Pythagorean theorem: \[ KL^2 + LM^2 = KN^2 \] \[ (2k)^2 + (5k)^2 = KN^2 \] \[ 4k^2 + 25k^2 = KN^2 \] \[ 29k^2 = KN^2 \] \[ KN = \sqrt{29}k \]

Step 5: Solve for \( k \)

The perimeter equation becomes: \[ 2k + 5k + \sqrt{29}k + k = 56 \] \[ 8k + \sqrt{29}k = 56 \] \[ k(8 + \sqrt{29}) = 56 \] \[ k = \frac{56}{8 + \sqrt{29}} \]

Step 6: Simplify \( k \)

To simplify \( k \), rationalize the denominator: \[ k = \frac{56(8 - \sqrt{29})}{(8 + \sqrt{29})(8 - \sqrt{29})} \] \[ k = \frac{56(8 - \sqrt{29})}{64 - 29} \] \[ k = \frac{56(8 - \sqrt{29})}{35} \] \[ k = \frac{56}{35}(8 - \sqrt{29}) \] \[ k = \frac{8}{5}(8 - \sqrt{29}) \]

Step 7: Calculate \( AB \)

Since \( AC = BC = x \) and \( AB = x\sqrt{2} \), we need to find \( x \). Given \( AC = BC \) and the perimeter of \( \triangle ABC \) is \( 56 \) cm, we can use the relationship: \[ AC + BC + AB = 56 \] \[ x + x + x\sqrt{2} = 56 \] \[ 2x + x\sqrt{2} = 56 \] \[ x(2 + \sqrt{2}) = 56 \] \[ x = \frac{56}{2 + \sqrt{2}} \]

Step 8: Simplify \( x \)

Rationalize the denominator: \[ x = \frac{56(2 - \sqrt{2})}{(2 + \sqrt{2})(2 - \sqrt{2})} \] \[ x = \frac{56(2 - \sqrt{2})}{4 - 2} \] \[ x = \frac{56(2 - \sqrt{2})}{2} \] \[ x = 28(2 - \sqrt{2}) \]

Final Answer

\[ AB = x\sqrt{2} = 28(2 - \sqrt{2})\sqrt{2} \] \[ AB = 28(2\sqrt{2} - 2) \] \[ AB = 56\sqrt{2} - 56 \]

Thus, the length of \( AB \) is \( 56\sqrt{2} - 56 \) cm.

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