Questions: Solve for a Variable (FA24)
Question 1, *Quick Check IR2.IR5.23
Part 1 of 2
The area A of a triangle is given by the formula A=1/2 bh, where b is the base of the triangle and h is the height.
(a) Solve the formula for b.
(b) Find the base of the triangle whose area is 18 square inches and whose height is 9 inches.
Transcript text: Solve for a Variable (FA24)
Question 1, *Quick Check IR2.IR5.23
Part 1 of 2
The area $A$ of a triangle is given by the formula $A=\frac{1}{2} b h$, where $b$ is the base of the triangle and $h$ is the height.
(a) Solve the formula for $b$.
(b) Find the base of the triangle whose area is 18 square inches and whose height is 9 inches.
Solution
Solution Steps
Solution Approach
To solve for the base \( b \) in the formula for the area of a triangle \( A = \frac{1}{2} b h \), we need to isolate \( b \) on one side of the equation. This can be done by multiplying both sides by 2 and then dividing by \( h \). For part (b), substitute the given values of area and height into the rearranged formula to find the base.
Step 1: Rearrange the Formula to Solve for \( b \)
The area of a triangle is given by the formula:
\[
A = \frac{1}{2} b h
\]
To solve for the base \( b \), we need to isolate \( b \) on one side of the equation. Multiply both sides by 2 to eliminate the fraction:
\[
2A = b h
\]
Next, divide both sides by \( h \) to solve for \( b \):
\[
b = \frac{2A}{h}
\]
Step 2: Substitute Given Values to Find \( b \)
Given that the area \( A = 18 \) square inches and the height \( h = 9 \) inches, substitute these values into the formula: