To find the value of the function f(x)=2⋅2+5x−9 f(x) = 2 \cdot 2 + 5x - 9 f(x)=2⋅2+5x−9 at x=−3 x = -3 x=−3, substitute −3-3−3 for x x x in the function and simplify the expression.
To evaluate the function f(x)=2⋅2+5x−9 f(x) = 2 \cdot 2 + 5x - 9 f(x)=2⋅2+5x−9 at x=−3 x = -3 x=−3, substitute −3-3−3 for x x x:
f(−3)=2⋅2+5(−3)−9 f(-3) = 2 \cdot 2 + 5(-3) - 9 f(−3)=2⋅2+5(−3)−9
First, calculate the constant term:
2⋅2=4 2 \cdot 2 = 4 2⋅2=4
Next, calculate the term involving x x x:
5(−3)=−15 5(-3) = -15 5(−3)=−15
Now, substitute these values back into the expression:
f(−3)=4−15−9 f(-3) = 4 - 15 - 9 f(−3)=4−15−9
Simplify the expression by performing the arithmetic operations:
f(−3)=4−15−9=−20 f(-3) = 4 - 15 - 9 = -20 f(−3)=4−15−9=−20
The value of the function evaluated at f(−3) f(-3) f(−3) is −20\boxed{-20}−20.
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