Use the property of square roots that states a⋅b=a⋅b\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}a⋅b=a⋅b.
14⋅21=14⋅21 \sqrt{14} \cdot \sqrt{21} = \sqrt{14 \cdot 21} 14⋅21=14⋅21
Calculate the product of the numbers inside the square root.
14⋅21=294 14 \cdot 21 = 294 14⋅21=294
Simplify 294\sqrt{294}294 by finding the prime factorization of 294 and identifying any perfect squares.
Prime factorization of 294: 294=2×3×7×7294 = 2 \times 3 \times 7 \times 7294=2×3×7×7.
Since 7×7=497 \times 7 = 497×7=49 is a perfect square, we can simplify:
294=2×3×49=2×3×49=6×7 \sqrt{294} = \sqrt{2 \times 3 \times 49} = \sqrt{2 \times 3} \times \sqrt{49} = \sqrt{6} \times 7 294=2×3×49=2×3×49=6×7
Thus, the expression simplifies to:
76 7\sqrt{6} 76
76\boxed{7\sqrt{6}}76
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