Use the property of square roots that states \(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\).
\[ \sqrt{14} \cdot \sqrt{21} = \sqrt{14 \cdot 21} \]
Calculate the product of the numbers inside the square root.
\[ 14 \cdot 21 = 294 \]
Simplify \(\sqrt{294}\) by finding the prime factorization of 294 and identifying any perfect squares.
Prime factorization of 294: \(294 = 2 \times 3 \times 7 \times 7\).
Since \(7 \times 7 = 49\) is a perfect square, we can simplify:
\[ \sqrt{294} = \sqrt{2 \times 3 \times 49} = \sqrt{2 \times 3} \times \sqrt{49} = \sqrt{6} \times 7 \]
Thus, the expression simplifies to:
\[ 7\sqrt{6} \]
\(\boxed{7\sqrt{6}}\)
Oops, Image-based questions are not yet availableUse Solvely.ai for full features.
Failed. You've reached the daily limit for free usage.Please come back tomorrow or visit Solvely.ai for additional homework help.