Questions: Complete the sentence below. The point on the unit circle that corresponds to θ=π/4 is P=.

Complete the sentence below.
The point on the unit circle that corresponds to θ=π/4 is P=.
Transcript text: Complete the sentence below. The point on the unit circle that corresponds to $\theta=\frac{\pi}{4}$ is $P=$ $\qquad$ .
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Solution

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Solution Steps

Step 1: Recall the unit circle definition

The unit circle is defined as a circle with a radius of 1 centered at the origin \((0, 0)\) in the coordinate plane. Any angle \(\theta\) measured from the positive \(x\)-axis corresponds to a point \(P = (x, y)\) on the unit circle, where \(x = \cos(\theta)\) and \(y = \sin(\theta)\).

Step 2: Substitute \(\theta = \frac{\pi}{4}\) into the trigonometric functions

For \(\theta = \frac{\pi}{4}\), calculate \(x\) and \(y\): \[ x = \cos\left(\frac{\pi}{4}\right), \quad y = \sin\left(\frac{\pi}{4}\right). \]

Step 3: Evaluate \(\cos\left(\frac{\pi}{4}\right)\) and \(\sin\left(\frac{\pi}{4}\right)\)

From trigonometric identities: \[ \cos\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}, \quad \sin\left(\frac{\pi}{4}\right) = \frac{\sqrt{2}}{2}. \]

Step 4: Write the ordered pair \(P\)

Substitute the values of \(x\) and \(y\) into the ordered pair: \[ P = \left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right). \]

Final Answer

\( P = \left(\frac{\sqrt{2}}{2}, \frac{\sqrt{2}}{2}\right) \)

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