Questions: Find the numerical value if (x=5) and (y=1). (4 x^2+6 y) (4 x^2+6 y=) (Simplify your answer. Type an integer or a fraction.)

$Find the numerical value if (x=5) and (y=1). (4 x^2+6 y) (4 x^2+6 y=) (Simplify your answer. Type an integer or a fraction.)$

Transcript text: Find the numerical value if $x=5$ and $y=1$. \[ 4 x^{2}+6 y \] \[ 4 x^{2}+6 y= \] $\square$ (Simplify your answer. Type an integer or a fraction.)

Solution

Solution Steps

Step 1: Substitute the Given Values

Substitute $x = 5$ and $y = 1$ into the expression $4x^2 + 6y$ .

$4(5)^2 + 6(1)$

Step 2: Calculate

4x^2

Calculate $4 \times 5^2$ .

$4 \times 25 = 100$

Step 3: Calculate

6y

Calculate $6 \times 1$ .

$6 \times 1 = 6$

Step 4: Add the Results

Add the results from Step 2 and Step 3.

$100 + 6 = 106$

Final Answer

The numerical value of the expression is $\boxed{106}$ .

Was this solution helpful?

Unhelpful

Helpful

Questions asked by other users

< Previous Next >

Thank you for your feedback.

Copied!