Questions: Find the numerical value if (x=5) and (y=1). (4 x^2+6 y) (4 x^2+6 y=) (Simplify your answer. Type an integer or a fraction.)

Find the numerical value if (x=5) and (y=1).

(4 x^2+6 y)

(4 x^2+6 y=)

(Simplify your answer. Type an integer or a fraction.)
Transcript text: Find the numerical value if $x=5$ and $y=1$. \[ 4 x^{2}+6 y \] \[ 4 x^{2}+6 y= \] $\square$ (Simplify your answer. Type an integer or a fraction.)
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Solution

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Solution Steps

Step 1: Substitute the Given Values

Substitute x=5x = 5 and y=1y = 1 into the expression 4x2+6y4x^2 + 6y.

4(5)2+6(1) 4(5)^2 + 6(1)

Step 2: Calculate 4x24x^2

Calculate 4×524 \times 5^2.

4×25=100 4 \times 25 = 100

Step 3: Calculate 6y6y

Calculate 6×16 \times 1.

6×1=6 6 \times 1 = 6

Step 4: Add the Results

Add the results from Step 2 and Step 3.

100+6=106 100 + 6 = 106

Final Answer

The numerical value of the expression is 106\boxed{106}.

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