Questions: Find the numerical value if (x=5) and (y=1). (4 x^2+6 y) (4 x^2+6 y=) (Simplify your answer. Type an integer or a fraction.)

$Find the numerical value if (x=5) and (y=1). (4 x^2+6 y) (4 x^2+6 y=) (Simplify your answer. Type an integer or a fraction.)$

Transcript text: Find the numerical value if $x=5$ and $y=1$. \[ 4 x^{2}+6 y \] \[ 4 x^{2}+6 y= \] $\square$ (Simplify your answer. Type an integer or a fraction.)

Solution

Solution Steps

Step 1: Substitute the Given Values

Substitute $x = 5$ and $y = 1$ into the expression $4x^2 + 6y$.

\[ 4(5)^2 + 6(1) \]

Step 2: Calculate $4x^2$

Calculate $4 \times 5^2$.

\[ 4 \times 25 = 100 \]

Step 3: Calculate $6y$

Calculate $6 \times 1$.

\[ 6 \times 1 = 6 \]

Step 4: Add the Results

Add the results from Step 2 and Step 3.

\[ 100 + 6 = 106 \]

Final Answer

The numerical value of the expression is $\boxed{106}$.

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