Questions: Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below. Lengths (mm) Frequency ------ 60-69 1 70-79 16 80-89 71 90-99 108 100-109 83 110-119 18 120-129 3 What is the lower class boundary for the first class? class boundary =

Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm) is summarized in the GFDT below.

Lengths (mm) Frequency
------
60-69 1
70-79 16
80-89 71
90-99 108
100-109 83
110-119 18
120-129 3

What is the lower class boundary for the first class?
class boundary =

Transcript text: Data was collected for 300 fish from the North Atlantic. The length of the fish (in mm ) is summarized in the GFDT below. \begin{tabular}{|c|c|} \hline Lengths $(\mathrm{mm})$ & Frequency \\ \hline $60-69$ & 1 \\ \hline $70-79$ & 16 \\ \hline $80-89$ & 71 \\ \hline $90-99$ & 108 \\ \hline $100-109$ & 83 \\ \hline $110-119$ & 18 \\ \hline $120-129$ & 3 \\ \hline \end{tabular} What is the lower class boundary for the first class? class boundary $=$ $\square$

Solution

Solution Steps

Step 1: Understand the concept of lower class boundary

The lower class boundary is the smallest value that can belong to a given class interval. It is calculated by subtracting half of the gap between consecutive intervals from the lower limit of the class.

Step 2: Identify the first class interval

The first class interval in the table is $60-69$.

Step 3: Calculate the lower class boundary

The gap between consecutive intervals is $70 - 69 = 1$. Therefore, the lower class boundary for the first class is: \[ \text{Lower Class Boundary} = 60 - \frac{1}{2} = 59.5 \]

Final Answer

\[ \boxed{59.5} \]

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