To solve the problem, we need to calculate the total interest earned for different types of interest rates.
- For simple interest, use the formula \( I = P \times r \times t \).
- For compound interest, use the formula \( A = P \times (1 + \frac{r}{n})^{n \times t} \) and then subtract the principal \( P \) to get the interest.
Given:
- Principal \( P = 26000 \)
- Rate \( r = 0.08 \)
- Time \( t = 20 \) years
We will calculate:
(a) Simple interest
(b) Compound interest compounded annually
(c) Compound interest compounded quarterly
(d) Compound interest compounded monthly
The formula for simple interest is given by:
\[ I = P \times r \times t \]
where:
- \( P = 26000 \)
- \( r = 0.08 \)
- \( t = 20 \)
Substituting the values, we get:
\[ I = 26000 \times 0.08 \times 20 = 41600 \]
The formula for compound interest is given by:
\[ A = P \times \left(1 + \frac{r}{n}\right)^{n \times t} \]
where:
- \( P = 26000 \)
- \( r = 0.08 \)
- \( t = 20 \)
- \( n = 1 \) (compounded annually)
Substituting the values, we get:
\[ A = 26000 \times \left(1 + \frac{0.08}{1}\right)^{1 \times 20} = 121184.8857 \]
The compound interest is:
\[ I = A - P = 121184.8857 - 26000 = 95184.8857 \]
Using the same formula for compound interest with:
- \( n = 4 \) (compounded quarterly)
Substituting the values, we get:
\[ A = 26000 \times \left(1 + \frac{0.08}{4}\right)^{4 \times 20} = 126761.4181 \]
The compound interest is:
\[ I = A - P = 126761.4181 - 26000 = 100761.4181 \]
Using the same formula for compound interest with:
- \( n = 12 \) (compounded monthly)
Substituting the values, we get:
\[ A = 26000 \times \left(1 + \frac{0.08}{12}\right)^{12 \times 20} = 128096.8720 \]
The compound interest is:
\[ I = A - P = 128096.8720 - 26000 = 102096.8720 \]