The expression under the square root, 4+x 4 + x 4+x, must be non-negative. Therefore: 4+x≥0 4 + x \geq 0 4+x≥0 x≥−4 x \geq -4 x≥−4
The denominator, 7−x 7 - x 7−x, cannot be zero. Therefore: 7−x≠0 7 - x \neq 0 7−x=0 x≠7 x \neq 7 x=7
The domain of g(x) g(x) g(x) is all real numbers x x x such that x≥−4 x \geq -4 x≥−4 and x≠7 x \neq 7 x=7. In interval notation, this is: [−4,7)∪(7,∞) [-4, 7) \cup (7, \infty) [−4,7)∪(7,∞)
[−4,7)∪(7,∞)\boxed{[-4, 7) \cup (7, \infty)}[−4,7)∪(7,∞)
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