Questions: Caladan is currently one of the world's fastest-growing countries. The exponential function f(x)=55(1.034)^x models the population of Caladan, f(x), in millions, x years after 1974. Using this exponential function and a calculator with a y* key or a ^ key, answer the following questions.
a. Substitute 0 for x and, without using a calculator, find Caladan's population in 1974.
55 million
b. Substitute 21 for x and use your calculator to find Caladan's population in the year 1995 as predicted by this function.
million (Round to the nearest tenth.)
Transcript text: Caladan is currently one of the world's fastest-growing countries. The exponential function $f(x)=55(1.034)^{x}$ models the population of Caladan, $f(x)$, in millions, $x$ years after 1974 . Using this exponential function and a calculator with a $y^{\star}$ key or a ^key, answer the following questions.
a. Substitute 0 for x and, without using a calculator, find Caladan's population in 1974.
55 million
b. Substitute 21 for x and use your calculator to find Caladan's population in the year 1995 as predicted by this function.
$\square$ million (Round to the nearest tenth.)
Solution
Solution Steps
Step 1: Substitute \( x = 0 \) into the function
Substitute \( x = 0 \) into the exponential function \( f(x) = 55(1.034)^{x} \):
\[
f(0) = 55(1.034)^{0}.
\]
Since any number raised to the power of 0 is 1, this simplifies to:
\[
f(0) = 55 \times 1 = 55.
\]
Thus, Caladan's population in 1974 was 55 million.
Step 2: Substitute \( x = 21 \) into the function
Substitute \( x = 21 \) into the exponential function \( f(x) = 55(1.034)^{x} \):
\[
f(21) = 55(1.034)^{21}.
\]
Step 3: Calculate \( (1.034)^{21} \) using a calculator
Use a calculator to compute \( (1.034)^{21} \):
\[
(1.034)^{21} \approx 2.039.
\]
Step 4: Multiply by 55 to find the population
Multiply the result by 55 to find the population in 1995:
\[
f(21) = 55 \times 2.039 \approx 112.145.
\]
Round to the nearest tenth:
\[
f(21) \approx 112.1.
\]
Thus, Caladan's population in 1995 was approximately 112.1 million.
Final Answer
a. \(\boxed{55}\) million
b. \(\boxed{112.1}\) million