Questions: What is the mass of 49.23 mL of saline (salt water) solution that has a density of 1.3236 g mL^-1? Identify Conversion Factor: - 1 mL= g

Transcript text: What is the mass of 49.23 mL of saline (salt water) solution that has a density of $1.3236 \mathrm{~g} \mathrm{~mL}^{-1}$ ? Identify Conversion Factor: - $1 \mathrm{~mL}=$ $\square$ g Question Help: Video Submit Part

Solution

Solution Steps

Step 1: Identify the Given Values

We are given the volume of the saline solution and its density:

Volume, $ V = 49.23 \, \text{mL} $
Density, $ \rho = 1.3236 \, \text{g} \, \text{mL}^{-1} $

Step 2: Use the Density Formula

The formula to find mass using density and volume is: \[ \text{Mass} = \text{Density} \times \text{Volume} \]

Step 3: Calculate the Mass

Substitute the given values into the formula: \[ \text{Mass} = 1.3236 \, \text{g} \, \text{mL}^{-1} \times 49.23 \, \text{mL} \]

Step 4: Perform the Multiplication

\[ \text{Mass} = 65.1457 \, \text{g} \]

Step 5: Round to Four Significant Digits

Since the density is given to four significant digits, we should round the mass to four significant digits as well: \[ \text{Mass} \approx 65.15 \, \text{g} \]