Questions: What is the mass of 49.23 mL of saline (salt water) solution that has a density of 1.3236 g mL^-1? Identify Conversion Factor: - 1 mL= g

Solution Steps

We are given the volume of the saline solution and its density:

• Volume, \( V = 49.23 \, \text{mL} \)
• Density, \( \rho = 1.3236 \, \text{g} \, \text{mL}^{-1} \)

The formula to find mass using density and volume is: \[ \text{Mass} = \text{Density} \times \text{Volume} \]

Substitute the given values into the formula: \[ \text{Mass} = 1.3236 \, \text{g} \, \text{mL}^{-1} \times 49.23 \, \text{mL} \]

\[ \text{Mass} = 65.1457 \, \text{g} \]

Since the density is given to four significant digits, we should round the mass to four significant digits as well: \[ \text{Mass} \approx 65.15 \, \text{g} \]

Final Answer