Questions: Which set has the lowest potential energy? A) a +2 charge and a +2 charge separated by distance of 2x B) a +2 charge and a +2 charge separated by distance of x C) a +2 charge and a -2 charge separated by distance of 2x D) a +2 charge and a -2 charge separated by distance of x
Transcript text: 18) Which set has the lowest potential energy?
A) a +2 charge and a +2 charge separated by distance of $2 x$
B) a +2 charge and $a+2$ charge separated by distance of $x$
C) $a+2$ charge and a -2 charge separated by distance of $2 x$
D) a +2 charge and a - 2 charge separated by distance of $x$
Solution
Solution Steps
Step 1: Understanding the Concept of Electric Potential Energy
Electric potential energy between two point charges is given by the formula:
\[
U = k \frac{q_1 q_2}{r}
\]
where \( U \) is the potential energy, \( k \) is Coulomb's constant, \( q_1 \) and \( q_2 \) are the charges, and \( r \) is the distance between the charges. The potential energy is positive if both charges have the same sign and negative if they have opposite signs.
Step 2: Calculate Potential Energy for Each Option
Let's calculate the potential energy for each option:
Option A: Two +2 charges separated by distance \( 2x \).
\[
U_A = k \frac{(+2)(+2)}{2x} = k \frac{4}{2x} = \frac{2k}{x}
\]
Option B: Two +2 charges separated by distance \( x \).
\[
U_B = k \frac{(+2)(+2)}{x} = k \frac{4}{x}
\]
Option C: A +2 charge and a -2 charge separated by distance \( 2x \).
\[
U_C = k \frac{(+2)(-2)}{2x} = k \frac{-4}{2x} = \frac{-2k}{x}
\]
Option D: A +2 charge and a -2 charge separated by distance \( x \).
\[
U_D = k \frac{(+2)(-2)}{x} = k \frac{-4}{x}
\]
Step 3: Compare the Potential Energies
Now, compare the potential energies calculated:
\( U_A = \frac{2k}{x} \)
\( U_B = \frac{4k}{x} \)
\( U_C = \frac{-2k}{x} \)
\( U_D = \frac{-4k}{x} \)
The lowest potential energy is the most negative value. Among these, \( U_D = \frac{-4k}{x} \) is the most negative.
Final Answer
The set with the lowest potential energy is option D: \(\boxed{\text{D}}\).