Questions: Problem 6: (10% of Assignment Value) Consider the following three forces: - F1 = (301 N) i + (467 N) j - F2 = (-173 N) i - F3 = (-639 N) j - Part (a) What is the x component, in newtons, of the net force? Fsecx = 128.0 N ✓ Correct! - Part (b) v What is the y component, in newtons, of the net force? - Fsay = -172 - Fseay = -172.0 N ✓ Correct! - Part (c) What is the magnitude, in newtons, of the net force? - Fed = 128 + (-172) - Fset = -44.00 N X Incorrect! Give Up used. Part (d) What is the direction of the net force? Express your answer as the angle which is measured counterclockwise, in degrees, from the positive x axis. θ=

Transcript text: Problem 6: ( $10 \%$ of Assignment Value) Consider the following three forces: \[ \begin{array}{l} \vec{F}_{1}=(301 \mathrm{~N}) \hat{i}+(467 \mathrm{~N}) \hat{j} \\ \vec{F}_{2}=(-173 \mathrm{~N}) \hat{i} \\ \vec{F}_{3}=(-639 \mathrm{~N}) \hat{j} \end{array} \] - Part (a) What is the $x$ component, in newtons, of the net force? \[ F_{\text {secx }}=128.0 \mathrm{~N} \] $\checkmark$ Correct! - Part (b) $\boldsymbol{v}$ What is the $y$ component, in newtons, of the net force? \[ \begin{array}{l} F_{\text {say }}=-172 \\ F_{\text {seay }}=-172.0 \mathrm{~N} \end{array} \] $\checkmark$ Correct! - Part (c) What is the magnitude, in newtons, of the net force? \[ \begin{array}{l} F_{\text {ed }}=128+(-172) \\ F_{\text {set }}=-44.00 \mathrm{~N} \quad \text { X Incorrect! Give Up used. } \end{array} \] Part (d) What is the direction of the net force? Express your answer as the angle which is measured counterclockwise, in degrees, from the positive $x$ axis. \[ \theta= \]