Questions: Chapter 2 Quiz Question 2 of 8 (1 point) Question Attempt: 1 of 1 Draw the bond-line (skeletal) formula of a compound with the molecular formula C5H10Br2 that meets the specified condition. Part 1 of 2 All of the carbon atoms belong to methylene (-CH2-) groups.

Chapter 2 Quiz Question 2 of 8 (1 point) Question Attempt: 1 of 1

Draw the bond-line (skeletal) formula of a compound with the molecular formula C5H10Br2 that meets the specified condition.

Part 1 of 2

All of the carbon atoms belong to methylene (-CH2-) groups.
Transcript text: Chapter 2 Quiz Question 2 of 8 (1 point) I Question Attempt: 1 of 1 Draw the bond-line (skeletal) formula of a compound with the molecular formula $\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{Br}_{2}$ that meets the specified condition. Part 1 of 2 All of the carbon atoms belong to methylene $\left(-\mathrm{CH}_{2}-\right)$ groups.
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Solution

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Solution Steps

Step 1: Identify the Structure

To meet the condition that all carbon atoms belong to methylene (\(-\mathrm{CH}_{2}-\)) groups, we need to arrange the carbon atoms in such a way that each carbon is bonded to two hydrogen atoms and two other groups.

Step 2: Determine the Carbon Chain

Given the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{Br}_{2}\), we need a five-carbon chain where each carbon is part of a methylene group. This implies a straight chain of five carbons.

Step 3: Add Bromine Atoms

To satisfy the molecular formula, we need to add two bromine atoms to the structure. Since each carbon is a methylene group, we can place the bromine atoms on any two different carbons in the chain.

Step 4: Draw the Bond-Line Formula

The bond-line (skeletal) formula for the compound can be drawn as follows:

\[ \mathrm{Br}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{Br} \]

This structure ensures that all carbon atoms are part of methylene groups and the molecular formula \(\mathrm{C}_{5} \mathrm{H}_{10} \mathrm{Br}_{2}\) is satisfied.

Final Answer

\(\boxed{\text{Br-CH}_2\text{-CH}_2\text{-CH}_2\text{-CH}_2\text{-Br}}\)

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