Questions: The output of an economic system Q, subject to two inputs, such as labor L and capital K, is often modeled by the Cobb-Douglas production function Q=c L^a K^b. When a+b=1, the case is called constant returns to scale. Suppose Q=1451, a=8/9, b=1/9, and c=72. Complete parts (a) and (b).
a. Find the rate of change of capital with respect to labor, dK/dL. First substitute the given values of Q, a, b, and c into the production function.
Transcript text: The output of an economic system $Q$, subject to two inputs, such as labor $L$ and capital $K$, is often modeled by the Cobb-Douglas production function $Q=c L^{a} K^{b}$. When $a+b=1$, the case is called constant returns to scale. Suppose $Q=1451, a=\frac{8}{9}, b=\frac{1}{9}$, and $c=72$. Complete parts (a) and (b).
a. Find the rate of change of capital with respect to labor, $\frac{d K}{d L}$. First substitute the given values of $Q, a, b$, and $c$ into the production function.
Solution
Solution Steps
To find the rate of change of capital with respect to labor, \(\frac{dK}{dL}\), we need to use implicit differentiation on the Cobb-Douglas production function \(Q = c L^a K^b\). Given the values \(Q = 1451\), \(a = \frac{8}{9}\), \(b = \frac{1}{9}\), and \(c = 72\), we can substitute these into the function and then differentiate implicitly with respect to \(L\).
Solution Approach
Substitute the given values into the Cobb-Douglas production function.
Differentiate implicitly with respect to \(L\).
Solve for \(\frac{dK}{dL}\).
Step 1: Substitute Given Values into the Production Function
The Cobb-Douglas production function is given by:
\[ Q = c L^a K^b \]
We are given:
\[ Q = 1451 \]
\[ a = \frac{8}{9} \]
\[ b = \frac{1}{9} \]
\[ c = 72 \]
Substituting these values into the production function, we get:
\[ 1451 = 72 L^{\frac{8}{9}} K^{\frac{1}{9}} \]
Step 2: Solve for \( K \) in Terms of \( L \)
To find the rate of change of capital with respect to labor, we first need to express \( K \) in terms of \( L \). Rearrange the equation to solve for \( K \):
\[ 1451 = 72 L^{\frac{8}{9}} K^{\frac{1}{9}} \]
\[ \frac{1451}{72} = L^{\frac{8}{9}} K^{\frac{1}{9}} \]
\[ \left( \frac{1451}{72} \right)^9 = \left( L^{\frac{8}{9}} K^{\frac{1}{9}} \right)^9 \]
\[ \left( \frac{1451}{72} \right)^9 = L^8 K \]
\[ K = \frac{\left( \frac{1451}{72} \right)^9}{L^8} \]
Step 3: Differentiate \( K \) with Respect to \( L \)
Now, we differentiate \( K \) with respect to \( L \):
\[ K = \frac{\left( \frac{1451}{72} \right)^9}{L^8} \]
Let \( C = \left( \frac{1451}{72} \right)^9 \), then:
\[ K = \frac{C}{L^8} \]
Differentiate both sides with respect to \( L \):
\[ \frac{dK}{dL} = \frac{d}{dL} \left( \frac{C}{L^8} \right) \]
\[ \frac{dK}{dL} = C \cdot \frac{d}{dL} \left( L^{-8} \right) \]
\[ \frac{dK}{dL} = C \cdot (-8) L^{-9} \]
\[ \frac{dK}{dL} = -8C L^{-9} \]
Substitute back \( C = \left( \frac{1451}{72} \right)^9 \):
\[ \frac{dK}{dL} = -8 \left( \frac{1451}{72} \right)^9 L^{-9} \]
Final Answer
The rate of change of capital with respect to labor is:
\[ \boxed{\frac{dK}{dL} = -8 \left( \frac{1451}{72} \right)^9 L^{-9}} \]