Questions: Two sides and an angle (SSA) of a triangle are given. Determine whether the given measurements produce one triangle, two triangles, or no triangle at all. Solve each triangle that results a=12, b=18.2, A=25° Selected the correct choice below and, if necessary, fill in the answer boxes to complete your choice. (Round side lengths to the nearest tenth and angle measurements to the nearest degree as needed.) A. There is only one possible solution for the triangle. The measurements for the remaining side c and angles B and C are as follows. B ≈ C ≈ c ≈ B. There are two possible solutions for the triangle. The measurements for the solution with the smaller angle B are as follows. B1 ≈ c1 ≈ c1 ≈ The measurements for the solution with the larger angle B are as follows. B2 ≈ c2 ≈ c2 ≈ 1 C. There are no possible solutions for this triangle.

Two sides and an angle (SSA) of a triangle are given. Determine whether the given measurements produce one triangle, two triangles, or no triangle at all. Solve each triangle that results

a=12, b=18.2, A=25°

Selected the correct choice below and, if necessary, fill in the answer boxes to complete your choice. (Round side lengths to the nearest tenth and angle measurements to the nearest degree as needed.)
A. There is only one possible solution for the triangle. The measurements for the remaining side c and angles B and C are as follows.
B ≈ C ≈ c ≈
B. There are two possible solutions for the triangle.

The measurements for the solution with the smaller angle B are as follows.

B1 ≈ 

c1 ≈ c1 ≈ 

The measurements for the solution with the larger angle B are as follows.

B2 ≈ 

c2 ≈ 

c2 ≈ 1

C. There are no possible solutions for this triangle.
Transcript text: Two sides and an angle (SSA) of a triangle are given. Determine whether the given measurements produce one triangle, two triangles, or no triangle at all. Solve each triangle that results \[ \mathrm{a}=12, \quad \mathrm{~b}=18.2, \quad \mathrm{~A}=25^{\circ} \] Selected the correct choice below and, if necessary, fill in the answer boxes to complete your choice. (Round side lengths to the nearest tenth and angle measurements to the nearest degree as needed.) A. There is only one possible solution for the triangle. The measurements for the remaining side c and angles B and C are as follows. $B \approx$ $\square$ $C \approx$ $\square$ $c \approx$ $\square$ B. There are two possible solutions for the triangle. The measurements for the solution with the the smaller angle B are as follows. \[ \mathrm{B}_{1} \approx \square^{\circ} \] $\square$ \[ c_{1} \approx \square^{\circ} \quad c_{1} \approx \square \] $\square$ The measurements for the solution with the the larger angle $B$ are as follows. \[ \mathrm{B}_{2} \approx \] $\square$ \[ c_{2} \approx \] $\square$ \[ c_{2} \approx 1 \] $\square$ C. There are no possible solutions for this triangle.
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Solution

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Solution Steps

Step 1: Use the Law of Sines to find possible value(s) for angle B

Using the Law of Sines, we have $\frac{a}{\sin(A)} = \frac{b}{\sin(B)}$. Substituting the given values, we get $\sin(B) = \frac{18.2 \times \sin(25^\circ)}{12} = 0.641$.

Step 2: Check for the number of solutions

Since $\sin(B) < 1$ and $a < b$ with $A$ being acute, two solutions exist with $B = 40^\circ$ or $B = 140^\circ$.

Step 3: Solve for the remaining parts of the triangle(s)

For the first solution, $C = 180^\circ - A - B = 115^\circ$. For the second solution, $C = 180^\circ - A - B = 15^\circ$.

Final Answer: Two triangles can be formed.

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