Questions: Write an equation for a rational function with: Vertical asymptotes at x=-2 and x=1 x-intercepts at x=-1 and x=-4 Horizontal asymptote at y=6 y=

Write an equation for a rational function with:
Vertical asymptotes at x=-2 and x=1
x-intercepts at x=-1 and x=-4
Horizontal asymptote at y=6
y=
Transcript text: Write an equation for a rational function with: Vertical asymptotes at $x=-2$ and $x=1$ $x$-intercepts at $x=-1$ and $x=-4$ Horizontal asymptote at $y=6$ \[ y=\square \]
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Solution

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To construct a rational function with the given properties, we need to consider the following:

  • Vertical asymptotes occur where the denominator is zero, so the denominator should have factors corresponding to \(x = -2\) and \(x = 1\).
  • \(x\)-intercepts occur where the numerator is zero, so the numerator should have factors corresponding to \(x = -1\) and \(x = -4\).
  • A horizontal asymptote at \(y = 6\) suggests that the leading coefficients of the numerator and denominator should be adjusted to achieve this ratio.
Paso 1: Construcción del numerador

Dado que los interceptos en \(x\) son \(x = -1\) y \(x = -4\), el numerador se puede expresar como: \[ \text{numerador} = 6 \cdot (x + 1)(x + 4) \]

Paso 2: Construcción del denominador

Las asíntotas verticales se encuentran en \(x = -2\) y \(x = 1\), por lo que el denominador se puede expresar como: \[ \text{denominador} = (x + 2)(x - 1) \]

Paso 3: Formulación de la función racional

La función racional completa se puede escribir como: \[ y = \frac{6 \cdot (x + 1)(x + 4)}{(x + 2)(x - 1)} \]

Respuesta Final

\[ \boxed{y = \frac{6 \cdot (x + 1)(x + 4)}{(x + 2)(x - 1)}} \]

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