Questions: A sound wave has an equation
y=7 sin (58 pi t)
where t= time in seconds
What is its frequency?
[?] cycles/second
Transcript text: A sound wave has an equation
\[
y=7 \sin (58 \pi t)
\]
where $t=$ time in seconds
What is its frequency?
[?] cycles/second
Solution
Solution Steps
Step 1: Identify the General Form of the Sine Wave Equation
The general form of a sine wave equation is:
\[
y = A \sin(2 \pi f t)
\]
where:
\(A\) is the amplitude,
\(f\) is the frequency in cycles per second (Hz),
\(t\) is the time in seconds.
Step 2: Compare Given Equation with General Form
The given equation is:
\[
y = 7 \sin(58 \pi t)
\]
We need to compare this with the general form \(y = A \sin(2 \pi f t)\).
Step 3: Extract the Frequency Component
From the given equation, we see that the argument of the sine function is \(58 \pi t\). In the general form, the argument is \(2 \pi f t\). Therefore, we can set:
\[
58 \pi t = 2 \pi f t
\]
Step 4: Solve for the Frequency
To find the frequency \(f\), we divide both sides of the equation by \(2 \pi t\):
\[
58 \pi = 2 \pi f
\]
\[
f = \frac{58 \pi}{2 \pi} = 29
\]
Final Answer
The frequency of the sound wave is:
\[
\boxed{29 \text{ cycles/second}}
\]