To solve the expression \(7 \cdot(6+2)^{2}-3^{2}\), follow these steps:
First, we evaluate the expression inside the parentheses: \[ 6 + 2 = 8 \]
Next, we square the result from Step 1: \[ 8^2 = 64 \]
Now, we multiply the squared result by 7: \[ 7 \cdot 64 = 448 \]
We then calculate \(3^2\): \[ 3^2 = 9 \]
Finally, we subtract the result from Step 4 from the result of Step 3: \[ 448 - 9 = 439 \]
\(\boxed{439}\)
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