Questions: 7 ·(6+2)^2-3^2=

7 ·(6+2)^2-3^2=
Transcript text: $7 \cdot(6+2)^{2}-3^{2}=$
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Solution

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Solution Steps

To solve the expression \(7 \cdot(6+2)^{2}-3^{2}\), follow these steps:

  1. Calculate the expression inside the parentheses: \(6 + 2\).
  2. Square the result from step 1.
  3. Multiply the squared result by 7.
  4. Calculate \(3^2\).
  5. Subtract the result from step 4 from the result of step 3.
Step 1: Calculate the Expression Inside the Parentheses

First, we evaluate the expression inside the parentheses: \[ 6 + 2 = 8 \]

Step 2: Square the Result

Next, we square the result from Step 1: \[ 8^2 = 64 \]

Step 3: Multiply by 7

Now, we multiply the squared result by 7: \[ 7 \cdot 64 = 448 \]

Step 4: Calculate \(3^2\)

We then calculate \(3^2\): \[ 3^2 = 9 \]

Step 5: Subtract the Results

Finally, we subtract the result from Step 4 from the result of Step 3: \[ 448 - 9 = 439 \]

Final Answer

\(\boxed{439}\)

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