Questions: The value of k which makes the matrix [9 -2 -3; -8 1 -8; 7 k 4] singular is k =
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Attempt 6: 5 attempts remaining.
The value of $k$ which makes the matrix $\left[\begin{array}{ccc}9 & -2 & -3 \\ -8 & 1 & -8 \\ 7 & k & 4\end{array}\right]$ singular is $k=$ $\square$
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Solution
Solution Steps
To determine the value of \( k \) that makes the matrix singular, we need to find the value of \( k \) for which the determinant of the matrix is zero. A matrix is singular if and only if its determinant is zero.
Step 1: Define the Matrix and Calculate the Determinant
We start with the matrix:
\[
\begin{bmatrix}
9 & -2 & -3 \\
-8 & 1 & -8 \\
7 & k & 4
\end{bmatrix}
\]
To find the value of \( k \) that makes the matrix singular, we need to calculate its determinant and set it to zero.
To make the matrix singular, we set the determinant to zero:
\[
96k + 233 = 0
\]
Solving for \( k \):
\[
k = -\frac{233}{96}
\]
\[
k = -\frac{35}{32}
\]
Final Answer
The value of \( k \) that makes the matrix singular is:
\[
\boxed{k = -\frac{35}{32}}
\]