Questions: Use the following information to answer the next questions. Glucose is a biological fuel used by cells to satisfy the energy needs of plants and animals. The overall reaction for the metabolism of glucose is represented by the unbalanced equation -393564 -C6H12O6(s)+CO2(g) → 6 CO2(g)+ 2418 8 C2H2O(l) 43. The balanced equation and the enthalpy change for the cellular respiration of glucose can be represented as a. C6H12O6(s)+O2(g) → CO2(g)+H2O(l)+593.8 kJ b. C6H12O6(s)+6 O2(g)+2802.7 kJ → 6 CO2(g)+6 H2O (l) c. C6H12O6(s)+6 O2(g) → 6 CO2(g)+6 H2O(l)+2802.7 kJ d. C6H12O6(s)+6 O2(g) → 6 CO2(g)+6 H2O(l)+2538.7 kJ

Use the following information to answer the next questions. Glucose is a biological fuel used by cells to satisfy the energy needs of plants and animals. The overall reaction for the metabolism of glucose is represented by the unbalanced equation -393564 -C6H12O6(s)+CO2(g) → 6 CO2(g)+ 2418 8 C2H2O(l) 43. The balanced equation and the enthalpy change for the cellular respiration of glucose can be represented as a. C6H12O6(s)+O2(g) → CO2(g)+H2O(l)+593.8 kJ b. C6H12O6(s)+6 O2(g)+2802.7 kJ → 6 CO2(g)+6 H2O (l) c. C6H12O6(s)+6 O2(g) → 6 CO2(g)+6 H2O(l)+2802.7 kJ d. C6H12O6(s)+6 O2(g) → 6 CO2(g)+6 H2O(l)+2538.7 kJ
Transcript text: Use the following information to answer the next questions. Glucose is a biological fuel used by cells to satisfy the energy needs of plants and animals. The overall reaction for the metabolism of glucose is represented by the unbalanced equation \[ \begin{array}{l} -393564 \\ -\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s})+\mathrm{CO}_{2}(\mathrm{~g}) \rightarrow \underline{6} \mathrm{CO}_{2}(\mathrm{~g})+\underset{\mathrm{C}_{2} \mathrm{H}_{2} \mathrm{O}(\mathrm{l})}{2418} 8 \end{array} \] 43. The balanced equation and the enthalpy change for the cellular respiration of glucose can be represented as a. $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s})+\mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{CO}_{2}(\mathrm{~g})+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})+593.8 \mathrm{~kJ}$ b. $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s})+6 \mathrm{O}_{2}(\mathrm{~g})+2802.7 \mathrm{~kJ} \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}$ (l) c. $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s})+6 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+2802.7 \mathrm{~kJ}$ d. $\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s})+6 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g})+6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l})+2538.7 \mathrm{~kJ}$
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Solution

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Solution Steps

Step 1: Identify the Balanced Equation
  • The balanced equation for the cellular respiration of glucose is: \[ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s}) + 6 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g}) + 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \]
Step 2: Determine the Enthalpy Change
  • The enthalpy change (\(\Delta H\)) for the reaction is given as \( -2802.7 \, \mathrm{kJ} \). This indicates that the reaction releases energy.
Step 3: Match the Correct Option
  • The correct option should include the balanced equation and the enthalpy change as a product (since it is released): \[ \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s}) + 6 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g}) + 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) + 2802.7 \, \mathrm{kJ} \]
Step 4: Select the Correct Answer
  • The correct answer is: \[ \text{c. } \mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(\mathrm{~s}) + 6 \mathrm{O}_{2}(\mathrm{~g}) \rightarrow 6 \mathrm{CO}_{2}(\mathrm{~g}) + 6 \mathrm{H}_{2} \mathrm{O}(\mathrm{l}) + 2802.7 \, \mathrm{kJ} \]

Final Answer

The correct answer is C.

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