Questions: HO — C — CH2 — CH2 — C — OH CH3 — S — CH3 CH3CH2OH

HO — C — CH2 — CH2 — C — OH CH3 — S — CH3 CH3CH2OH
Transcript text: HO — C — CH_2 — CH_2 — C — OH CH_3 — S — CH_3 CH_3CH_2OH
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Solution

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Solution Steps

Step 1: Identify the Solute

The solute given is: \[ \text{HO — C — CH}_2 — \text{CH}_2 — \text{C — OH} \] This is a diol, specifically 1,3-propanediol, which is a polar compound due to the presence of hydroxyl (-OH) groups.

Step 2: Identify the Solvents

The two solvents provided are:

  1. \(\text{CH}_3 — \text{S} — \text{CH}_3\) (dimethyl sulfide)
  2. \(\text{CH}_3\text{CH}_2\text{OH}\) (ethanol)
Step 3: Determine Solvent Polarity
  • Dimethyl sulfide is a non-polar solvent because it lacks significant electronegative atoms that would create a dipole moment.
  • Ethanol is a polar solvent due to the presence of the hydroxyl (-OH) group, which can form hydrogen bonds.
Step 4: Match Solvent Polarity with Solute

Since 1,3-propanediol is a polar compound, it will dissolve better in a polar solvent. This is due to the principle "like dissolves like," where polar solutes are more soluble in polar solvents.

Final Answer

The better solvent for the solute 1,3-propanediol is ethanol (\(\text{CH}_3\text{CH}_2\text{OH}\)).

\[ \boxed{\text{Ethanol is the better solvent.}} \]

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