Questions: Find the area of the triangle defined by the points (2,1)(5,1)(2,8).

Find the area of the triangle defined by the points (2,1)(5,1)(2,8).
Transcript text: QUESTION 2 Find the area of the triangle defined by the points $(2,1)(5,1)(2,8)$. 10.5 units squared 21 units squared 9 units squared 8 units squared
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Solution

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Solution Steps

To find the area of a triangle given its vertices, we can use the formula for the area of a triangle with vertices \((x_1, y_1)\), \((x_2, y_2)\), and \((x_3, y_3)\):

\[ \text{Area} = \frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x_3(y_1-y_2) \right| \]

This formula calculates the absolute value of the determinant of a matrix formed by the coordinates, divided by 2.

Step 1: Identify the Vertices

The vertices of the triangle are given as \( (2, 1) \), \( (5, 1) \), and \( (2, 8) \).

Step 2: Apply the Area Formula

Using the area formula for a triangle defined by vertices \( (x_1, y_1) \), \( (x_2, y_2) \), and \( (x_3, y_3) \):

\[ \text{Area} = \frac{1}{2} \left| x_1(y_2-y_3) + x_2(y_3-y_1) + x3(y_1-y_2) \right| \]

Substituting the coordinates:

\[ \text{Area} = \frac{1}{2} \left| 2(1-8) + 5(8-1) + 2(1-1) \right| \]

Calculating the expression inside the absolute value:

\[ = \frac{1}{2} \left| 2(-7) + 5(7) + 2(0) \right| = \frac{1}{2} \left| -14 + 35 + 0 \right| = \frac{1}{2} \left| 21 \right| = \frac{21}{2} = 10.5 \]

Final Answer

The area of the triangle is \(\boxed{10.5}\).

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