Questions: The function (f) is defined as follows. [f(x)=sqrt[3]x-1] Find (f(64)) and (f(-125)). [f(64)=] [f(-125)=]

Solution Steps

To find the value of the function for a given \(x\), we first adjust the input by adding \(a\) to it. Thus, the new input for the cube root operation is \(x + a = 64 = 64\).

Next, we calculate the cube root of \(x + a\), which is \(\sqrt[3]{64}\). For our calculation, this value is \(4\).

Finally, we add \(b\) to the result of the cube root calculation to get the final output, \(f(x) = \sqrt[3]{64} - 1 = 3\).

Final Answer: The value of the function \(f(x) = \sqrt[3]{x + 0} - 1\) for \(x = 64\) is approximately 3.