Questions: [39+(6-3)^2] ÷ 8=?

Transcript text: $\left[39+(6-3)^{2}\right] \div 8=?$

Solution

Step 1: Simplify the expression inside the parentheses

First, simplify $(6 - 3)$ inside the parentheses: $(6 - 3) = 3$

Step 2: Calculate the exponent

Next, calculate $3^2$ : $3^2 = 9$

Step 3: Add the result to 39

Now, add the result to 39: $39 + 9 = 48$

Step 4: Divide by 8

Finally, divide the result by 8: $48 \div 8 = 6$

The final answer is $6$ .

$\boxed{6}$

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