Questions: [39+(6-3)^2] ÷ 8=?

Transcript text: $\left[39+(6-3)^{2}\right] \div 8=?$

Solution

Step 1: Simplify the expression inside the parentheses

First, simplify $ (6 - 3) $ inside the parentheses: \[ (6 - 3) = 3 \]

Step 2: Calculate the exponent

Next, calculate $ 3^2 $: \[ 3^2 = 9 \]

Step 3: Add the result to 39

Now, add the result to 39: \[ 39 + 9 = 48 \]

Step 4: Divide by 8

Finally, divide the result by 8: \[ 48 \div 8 = 6 \]

The final answer is $ 6 $.

$\boxed{6}$

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