Questions: [39+(6-3)^2] ÷ 8=?

[39+(6-3)^2] ÷ 8=?
Transcript text: $\left[39+(6-3)^{2}\right] \div 8=?$
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Solution

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Solution Steps

Step 1: Simplify the expression inside the parentheses

First, simplify (63) (6 - 3) inside the parentheses: (63)=3 (6 - 3) = 3

Step 2: Calculate the exponent

Next, calculate 32 3^2 : 32=9 3^2 = 9

Step 3: Add the result to 39

Now, add the result to 39: 39+9=48 39 + 9 = 48

Step 4: Divide by 8

Finally, divide the result by 8: 48÷8=6 48 \div 8 = 6

The final answer is 6 6 .

Final Answer

6\boxed{6}

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