The angles \(13x+6\) and \( \angle CAB \) are supplementary, so their measures add up to 180 degrees. \( m\angle CAB + 13x + 6 = 180 \) \( m\angle CAB = 180 - (13x+6) \) \( m\angle CAB = 174 - 13x \)
The angles \(70^{\circ}\) and \(\angle ACB\) are supplementary, so their measures add up to 180 degrees. \( m\angle ACB + 70 = 180 \) \( m\angle ACB = 180 - 70 \) \( m\angle ACB = 110 \)
The sum of the angles in triangle ABC is 180 degrees. \(m\angle ABC + m\angle ACB + m\angle CAB = 180\) \( 8 + 3x + 110 + 174 - 13x = 180 \) \( 292 - 10x = 180 \) \( -10x = 180 - 292 \) \( -10x = -112 \) \( x = \frac{-112}{-10} \) \( x = 11.2 \)
\( m\angle ABC = 8 + 3x \) \( m\angle ABC = 8 + 3(11.2) \) \( m\angle ABC = 8 + 33.6 \) \( m\angle ABC = 41.6 \)
\\(\boxed{m\angle ABC = 41.6^{\circ}}\\)
Oops, Image-based questions are not yet availableUse Solvely.ai for full features.
Failed. You've reached the daily limit for free usage.Please come back tomorrow or visit Solvely.ai for additional homework help.